Optimal. Leaf size=123 \[ \frac{a^{3/2} \tan ^{-1}\left (\frac{x^4 \sqrt{b c-a d}}{\sqrt{a} \sqrt{c+d x^8}}\right )}{4 b^2 \sqrt{b c-a d}}-\frac{(2 a d+b c) \tanh ^{-1}\left (\frac{\sqrt{d} x^4}{\sqrt{c+d x^8}}\right )}{8 b^2 d^{3/2}}+\frac{x^4 \sqrt{c+d x^8}}{8 b d} \]
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Rubi [A] time = 0.130621, antiderivative size = 123, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.292, Rules used = {465, 479, 523, 217, 206, 377, 205} \[ \frac{a^{3/2} \tan ^{-1}\left (\frac{x^4 \sqrt{b c-a d}}{\sqrt{a} \sqrt{c+d x^8}}\right )}{4 b^2 \sqrt{b c-a d}}-\frac{(2 a d+b c) \tanh ^{-1}\left (\frac{\sqrt{d} x^4}{\sqrt{c+d x^8}}\right )}{8 b^2 d^{3/2}}+\frac{x^4 \sqrt{c+d x^8}}{8 b d} \]
Antiderivative was successfully verified.
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Rule 465
Rule 479
Rule 523
Rule 217
Rule 206
Rule 377
Rule 205
Rubi steps
\begin{align*} \int \frac{x^{19}}{\left (a+b x^8\right ) \sqrt{c+d x^8}} \, dx &=\frac{1}{4} \operatorname{Subst}\left (\int \frac{x^4}{\left (a+b x^2\right ) \sqrt{c+d x^2}} \, dx,x,x^4\right )\\ &=\frac{x^4 \sqrt{c+d x^8}}{8 b d}-\frac{\operatorname{Subst}\left (\int \frac{a c+(b c+2 a d) x^2}{\left (a+b x^2\right ) \sqrt{c+d x^2}} \, dx,x,x^4\right )}{8 b d}\\ &=\frac{x^4 \sqrt{c+d x^8}}{8 b d}+\frac{a^2 \operatorname{Subst}\left (\int \frac{1}{\left (a+b x^2\right ) \sqrt{c+d x^2}} \, dx,x,x^4\right )}{4 b^2}-\frac{(b c+2 a d) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c+d x^2}} \, dx,x,x^4\right )}{8 b^2 d}\\ &=\frac{x^4 \sqrt{c+d x^8}}{8 b d}+\frac{a^2 \operatorname{Subst}\left (\int \frac{1}{a-(-b c+a d) x^2} \, dx,x,\frac{x^4}{\sqrt{c+d x^8}}\right )}{4 b^2}-\frac{(b c+2 a d) \operatorname{Subst}\left (\int \frac{1}{1-d x^2} \, dx,x,\frac{x^4}{\sqrt{c+d x^8}}\right )}{8 b^2 d}\\ &=\frac{x^4 \sqrt{c+d x^8}}{8 b d}+\frac{a^{3/2} \tan ^{-1}\left (\frac{\sqrt{b c-a d} x^4}{\sqrt{a} \sqrt{c+d x^8}}\right )}{4 b^2 \sqrt{b c-a d}}-\frac{(b c+2 a d) \tanh ^{-1}\left (\frac{\sqrt{d} x^4}{\sqrt{c+d x^8}}\right )}{8 b^2 d^{3/2}}\\ \end{align*}
Mathematica [A] time = 0.131722, size = 118, normalized size = 0.96 \[ \frac{\frac{2 a^{3/2} \tan ^{-1}\left (\frac{x^4 \sqrt{b c-a d}}{\sqrt{a} \sqrt{c+d x^8}}\right )}{\sqrt{b c-a d}}-\frac{(2 a d+b c) \log \left (\sqrt{d} \sqrt{c+d x^8}+d x^4\right )}{d^{3/2}}+\frac{b x^4 \sqrt{c+d x^8}}{d}}{8 b^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.067, size = 0, normalized size = 0. \begin{align*} \int{\frac{{x}^{19}}{b{x}^{8}+a}{\frac{1}{\sqrt{d{x}^{8}+c}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{19}}{{\left (b x^{8} + a\right )} \sqrt{d x^{8} + c}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.75201, size = 1638, normalized size = 13.32 \begin{align*} \left [\frac{2 \, \sqrt{d x^{8} + c} b d x^{4} + a d^{2} \sqrt{-\frac{a}{b c - a d}} \log \left (\frac{{\left (b^{2} c^{2} - 8 \, a b c d + 8 \, a^{2} d^{2}\right )} x^{16} - 2 \,{\left (3 \, a b c^{2} - 4 \, a^{2} c d\right )} x^{8} + a^{2} c^{2} + 4 \,{\left ({\left (b^{2} c^{2} - 3 \, a b c d + 2 \, a^{2} d^{2}\right )} x^{12} -{\left (a b c^{2} - a^{2} c d\right )} x^{4}\right )} \sqrt{d x^{8} + c} \sqrt{-\frac{a}{b c - a d}}}{b^{2} x^{16} + 2 \, a b x^{8} + a^{2}}\right ) +{\left (b c + 2 \, a d\right )} \sqrt{d} \log \left (-2 \, d x^{8} + 2 \, \sqrt{d x^{8} + c} \sqrt{d} x^{4} - c\right )}{16 \, b^{2} d^{2}}, \frac{2 \, \sqrt{d x^{8} + c} b d x^{4} + a d^{2} \sqrt{-\frac{a}{b c - a d}} \log \left (\frac{{\left (b^{2} c^{2} - 8 \, a b c d + 8 \, a^{2} d^{2}\right )} x^{16} - 2 \,{\left (3 \, a b c^{2} - 4 \, a^{2} c d\right )} x^{8} + a^{2} c^{2} + 4 \,{\left ({\left (b^{2} c^{2} - 3 \, a b c d + 2 \, a^{2} d^{2}\right )} x^{12} -{\left (a b c^{2} - a^{2} c d\right )} x^{4}\right )} \sqrt{d x^{8} + c} \sqrt{-\frac{a}{b c - a d}}}{b^{2} x^{16} + 2 \, a b x^{8} + a^{2}}\right ) + 2 \,{\left (b c + 2 \, a d\right )} \sqrt{-d} \arctan \left (\frac{\sqrt{-d} x^{4}}{\sqrt{d x^{8} + c}}\right )}{16 \, b^{2} d^{2}}, \frac{2 \, \sqrt{d x^{8} + c} b d x^{4} - 2 \, a d^{2} \sqrt{\frac{a}{b c - a d}} \arctan \left (-\frac{{\left ({\left (b c - 2 \, a d\right )} x^{8} - a c\right )} \sqrt{d x^{8} + c} \sqrt{\frac{a}{b c - a d}}}{2 \,{\left (a d x^{12} + a c x^{4}\right )}}\right ) +{\left (b c + 2 \, a d\right )} \sqrt{d} \log \left (-2 \, d x^{8} + 2 \, \sqrt{d x^{8} + c} \sqrt{d} x^{4} - c\right )}{16 \, b^{2} d^{2}}, \frac{\sqrt{d x^{8} + c} b d x^{4} - a d^{2} \sqrt{\frac{a}{b c - a d}} \arctan \left (-\frac{{\left ({\left (b c - 2 \, a d\right )} x^{8} - a c\right )} \sqrt{d x^{8} + c} \sqrt{\frac{a}{b c - a d}}}{2 \,{\left (a d x^{12} + a c x^{4}\right )}}\right ) +{\left (b c + 2 \, a d\right )} \sqrt{-d} \arctan \left (\frac{\sqrt{-d} x^{4}}{\sqrt{d x^{8} + c}}\right )}{8 \, b^{2} d^{2}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.39152, size = 140, normalized size = 1.14 \begin{align*} \frac{\sqrt{d x^{8} + c} x^{4}}{8 \, b d} - \frac{a^{2} \arctan \left (\frac{a \sqrt{d + \frac{c}{x^{8}}}}{\sqrt{a b c - a^{2} d}}\right )}{4 \, \sqrt{a b c - a^{2} d} b^{2}} + \frac{{\left (b c + 2 \, a d\right )} \arctan \left (\frac{\sqrt{d + \frac{c}{x^{8}}}}{\sqrt{-d}}\right )}{8 \, b^{2} \sqrt{-d} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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